(2^x×8^(x-1) ) ÷16^(x-1)
You asked:
Evaluate the expression: \(\frac{{2}^{x} \cdot {8}^{x - 1}}{{16}^{x - 1}}\)
MathBot Answer:
Evaluated
\(\displaystyle \frac{{2}^{x} \cdot {8}^{x - 1}}{{16}^{x - 1}} = 16^{1 - x} 2^{x} 8^{x - 1} \)
Expanded
\[\frac{{2}^{x} \cdot {8}^{x - 1}}{{16}^{x - 1}} = 2\]