pq-q^2 - 3p-3q
asked by guest on Apr 06, 2025 at 3:15 pm
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MathBot Answer:
pq−q2−3p−3q=pq−3p−q2−3qp q - {q}^{2} - 3 p - 3 q = p q - 3 p - q^{2} - 3 qpq−q2−3p−3q=pq−3p−q2−3q