y'^(2)-(2x+sinx)y'+2xsinx=0

asked by guest
on Jan 03, 2025 at 2:13 pm



You asked:

Investigate the equation: \({y^{\prime}}^{2} - \left(2 x + \sin\left( x \right)\right) \cdot y^{\prime} + 2 x \sin\left( x \right) = 0\).

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