Math Problem Solver

$$\frac{1}{3} + \frac{1}{4} = \frac{7}{12} = 0.58\overline{3}$$

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of $\frac{1}{3}$ and $\frac{1}{4}$ is $12$. $$\begin{aligned} \frac{1}{3} + \frac{1}{4} &= \frac{1 \cdot 4}{3 \cdot 4} + \frac{1 \cdot 3}{4 \cdot 3} \\ &= \frac{4 + 3}{12} \\ &= \frac{7}{12} \end{aligned}$$