e^x= 20

asked by guest
on Oct 18, 2024 at 3:14 am



You asked:

Investigate the equation: \({e}^{x} = 20\).

MathBot Answer:

The real solution is: \[x = \log{\left(20 \right)} \approx 2.9957323\]

The complex solutions are: \[\left\{2 n i \pi + \log{\left(20 \right)}\; \middle|\; n \in \mathbb{Z}\right\}\]

\(i\) is the imaginary unit, defined as \(i^2 = -1\).

\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).

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