√(x-y)^3
asked by guest on Nov 13, 2024 at 8:27 pm
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MathBot Answer:
x−y3=(x−y)32\displaystyle {\sqrt{x - y}}^{3} = \left(x - y\right)^{\frac{3}{2}} x−y3=(x−y)23
x−y3=xx−y−yx−y{\sqrt{x - y}}^{3} = x \sqrt{x - y} - y \sqrt{x - y}x−y3=xx−y−yx−y