(6p+1)(6p+1)

asked by guest
on Jan 18, 2025 at 3:51 pm



You asked:

Evaluate the expression: \(\left(6 p + 1\right) \left(6 p + 1\right)\)

MathBot Answer:

Evaluated



\(\displaystyle \left(6 p + 1\right) \left(6 p + 1\right) = \left(6 p + 1\right)^{2} \)

Expanded

\[\left(6 p + 1\right) \left(6 p + 1\right) = 36 p^{2} + 12 p + 1\]

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