y'=2xy $\frac{1}{\1+x²}$
You asked:
Investigate the equation: \(y^{\prime} = 2 x y \cdot \frac{1}{1 + {x}^{2}}\).
MathBot Answer:
\[y{\left(x \right)} = \left(1 + x^{2}\right) C_{1}\]
\(C_{1}\) is an arbitrary constant.
y'=2xy $\frac{1}{\1+x²}$
You asked:
MathBot Answer:
\[y{\left(x \right)} = \left(1 + x^{2}\right) C_{1}\]
\(C_{1}\) is an arbitrary constant.