what is 3 7/6+1/16
You asked:
Evaluate the expression: \(3\frac{7}{6} + \frac{1}{16}\)
MathBot Answer:
\[ 3\frac{7}{6} + \frac{1}{16} = \frac{203}{48} = 4.2291\overline{6} \]
The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{3}{1}\), \(\frac{7}{6}\), and \(\frac{1}{16}\) is \(48\). \[ \begin{aligned} 3\frac{7}{6} + \frac{1}{16} &= \frac{3 \cdot 48}{1 \cdot 48} + \frac{7 \cdot 8}{6 \cdot 8} + \frac{1 \cdot 3}{16 \cdot 3} \\ &= \frac{144 + 56 + 3}{48} \\ &= \frac{203}{48} \end{aligned} \]