= 9*6^n/35 - 2/5 + (-1)^n/7
asked by guest on Mar 28, 2025 at 6:19 pm
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MathBot Answer:
9⋅6n35−25+(−1)n7=(−1)n7+9⋅6n35−25\frac{9 \cdot {6}^{n}}{35} - \frac{2}{5} + \frac{{\left( -1 \right)}^{n}}{7} = \frac{\left(-1\right)^{n}}{7} + \frac{9 \cdot 6^{n}}{35} - \frac{2}{5}359⋅6n−52+7(−1)n=7(−1)n+359⋅6n−52