(6x³+5x²-10x+3)÷(2x-1)

asked by guest
on Nov 20, 2024 at 4:35 am



You asked:

Evaluate the expression: \(\frac{6 \cdot {x}^{3} + 5 \cdot {x}^{2} - 10 x + 3}{2 x - 1}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{6 \cdot {x}^{3} + 5 \cdot {x}^{2} - 10 x + 3}{2 x - 1} = \frac{6 x^{3} + 5 x^{2} - 10 x + 3}{2 x - 1} \)

Expanded

\[\frac{6 \cdot {x}^{3} + 5 \cdot {x}^{2} - 10 x + 3}{2 x - 1} = \frac{6 x^{3}}{2 x - 1} + \frac{5 x^{2}}{2 x - 1} - \frac{10 x}{2 x - 1} + \frac{3}{2 x - 1}\]

Factored

\[\frac{6 \cdot {x}^{3} + 5 \cdot {x}^{2} - 10 x + 3}{2 x - 1} = 3 x^{2} + 4 x - 3\]

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