=(3−λ)(λ^2−9λ+16)−20+4λ
You asked:
Evaluate the expression: \(\left(3 - λ\right) \cdot \left({λ}^{2} - 9 λ + 16\right) - 20 + 4 λ\)
MathBot Answer:
Evaluated
\(\displaystyle \left(3 - λ\right) \cdot \left({λ}^{2} - 9 λ + 16\right) - 20 + 4 λ = 4 λ + \left(3 - λ\right) \left(λ^{2} - 9 λ + 16\right) - 20 \)
Expanded
\[\left(3 - λ\right) \cdot \left({λ}^{2} - 9 λ + 16\right) - 20 + 4 λ = - λ^{3} + 12 λ^{2} - 39 λ + 28\]
Factored
\[\left(3 - λ\right) \cdot \left({λ}^{2} - 9 λ + 16\right) - 20 + 4 λ = - \left(λ - 7\right) \left(λ - 4\right) \left(λ - 1\right)\]