cot(A/z) + cot(B/z) + cot(c/2) = (a + b + c)/(a + c - a) * cot(A/2)

asked by guest
on Nov 13, 2024 at 12:16 pm



You asked:

Investigate the equation: cot⁡(Az)+cot⁡(Bz)+cot⁡(c2)=a+b+ca+c−acot⁡(A2)\cot\left( \frac{A}{z} \right) + \cot\left( \frac{B}{z} \right) + \cot\left( \frac{c}{2} \right) = \frac{a + b + c}{a + c - a} \cot\left( \frac{A}{2} \right).

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