Math Problem Solver

\[ 2\frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{37}{12} = 3.08\overline{3} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{2}{1}\), \(\frac{1}{2}\), \(\frac{1}{3}\), and \(\frac{1}{4}\) is \(12\). \[ \begin{aligned} 2\frac{1}{2} + \frac{1}{3} + \frac{1}{4} &= \frac{2 \cdot 12}{1 \cdot 12} + \frac{1 \cdot 6}{2 \cdot 6} + \frac{1 \cdot 4}{3 \cdot 4} + \frac{1 \cdot 3}{4 \cdot 3} \\ &= \frac{24 + 6 + 4 + 3}{12} \\ &= \frac{37}{12} \end{aligned} \]