factorize 4(x^3/2 -1)+1
You asked:
Factor the expression: \(\displaystyle 4 \cdot \left(\frac{{x}^{3}}{2} - 1\right) + 1\)
MathBot Answer:
Factorization over the rational numbers:
\[2 x^{3} - 3\]Factorization over the complex numbers:
\[2 \left(x - \frac{2^{\frac{2}{3}} \cdot \sqrt[3]{3}}{2}\right) \left(x + \left(\frac{2^{\frac{2}{3}} \cdot \sqrt[3]{3}}{4} - \frac{2^{\frac{2}{3}} \cdot 3^{\frac{5}{6}} i}{4}\right)\right) \left(x + \left(\frac{2^{\frac{2}{3}} \cdot \sqrt[3]{3}}{4} + \frac{2^{\frac{2}{3}} \cdot 3^{\frac{5}{6}} i}{4}\right)\right)\]\(i\) is the imaginary unit, defined as \(i^2 = -1\).
asked 2 days ago
active 2 days ago