2*(31-7y/3)
asked by guest on Apr 10, 2025 at 2:26 am
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MathBot Answer:
2(31−7y3)=62−14y3\displaystyle 2 \left(31 - \frac{7 y}{3}\right) = 62 - \frac{14 y}{3} 2(31−37y)=62−314y
2(31−7y3)=62−14y32 \left(31 - \frac{7 y}{3}\right) = 62 - \frac{14 y}{3}2(31−37y)=62−314y