1.300258628=(85.76721429((2.8)^2– (0.55+d)^2)(10)^3)/(4(0.55+d)(d) (10)^6 )

asked by guest
on Jan 20, 2025 at 12:49 am



You asked:

Solve the equation 1.300258628=85.76721429(2.82−(0.55+d)2)⋅1034(0.55+d)⋅d⋅1061.300258628 = \frac{85.76721429 \left({2.8}^{2} - {\left( 0.55 + d \right)}^{2}\right) \cdot {10}^{3}}{4 \left(0.55 + d\right) \cdot d \cdot {10}^{6}} for the variable dd.

MathBot Answer:

The 2 solutions to the equation are: d=−295491291731910573603452580+23500398935069920700652092643400863145≈0.16817546d=−295491291731910573603452580−23500398935069920700652092643400863145≈−0.72709805\begin{aligned}d &= - \frac{2954912917319}{10573603452580} + \frac{2 \sqrt{350039893506992070065209}}{2643400863145} \approx 0.16817546\\d &= - \frac{2954912917319}{10573603452580} - \frac{2 \sqrt{350039893506992070065209}}{2643400863145} \approx -0.72709805\end{aligned}

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