7^x+4 = 49^2x-1
You asked:
Solve the equation \({7}^{x} + 4 = {49}^{2} x - 1\) for the variable \(x\).
MathBot Answer:
The 2 solutions to the equation are: \[\begin{aligned}x &= \frac{0.000814412077336135446107882195296787605279666308398 + \frac{5 \log{\left(7 \right)}}{2401}}{\log{\left(7 \right)}} \approx 0.0025009907\\x &= \frac{9.34914319704207787712545074415690769560289626031 + \frac{5 \log{\left(7 \right)}}{2401}}{\log{\left(7 \right)}} \approx 4.8065917\end{aligned}\]