7^x+4 = 49^2x-1

asked by guest
on Jan 13, 2025 at 3:52 am



You asked:

Solve the equation 7x+4=492x−1{7}^{x} + 4 = {49}^{2} x - 1 for the variable xx.

MathBot Answer:

The 2 solutions to the equation are: x=0.000814412077336135446107882195296787605279666308398+5log⁡(7)2401log⁡(7)≈0.0025009907x=9.34914319704207787712545074415690769560289626031+5log⁡(7)2401log⁡(7)≈4.8065917\begin{aligned}x &= \frac{0.000814412077336135446107882195296787605279666308398 + \frac{5 \log{\left(7 \right)}}{2401}}{\log{\left(7 \right)}} \approx 0.0025009907\\x &= \frac{9.34914319704207787712545074415690769560289626031 + \frac{5 \log{\left(7 \right)}}{2401}}{\log{\left(7 \right)}} \approx 4.8065917\end{aligned}

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