7+2(-41÷13)÷3

asked by guest
on Jan 24, 2025 at 3:08 am



You asked:

Evaluate the expression: \(7 + \frac{2 \cdot \frac{-41}{13}}{3}\)

MathBot Answer:

\[7 + \frac{2 \cdot \frac{-41}{13}}{3} = \frac{191}{39} = 4.\overline{897435}\]

\[\begin{aligned}7 + \frac{2 \cdot \frac{-41}{13}}{3}& = 7 + 2 \cdot - \frac{41}{13} \cdot \frac{1}{3}\\& = 7 + 2 \cdot - \frac{41}{39}\\& = 7 - \frac{82}{39}\\& = \frac{191}{39}\end{aligned}\]

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