x + y + z = 11
number of ways to do this, given x,y,x are faces of a regular six faced dice.
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
x + y + z = 11
number of ways to do this, given x,y,x are faces of a regular six faced dice.
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.