Math Problem Solver

$$\frac{20}{1 + 125 {e}^{-\left( 0.8 \cdot 6.413 \right)}} = \frac{20}{\frac{125}{e^{\frac{6413}{1250}}} + 1} \approx 11.4990488337761165987858946651385$$

$$\begin{aligned}\frac{20}{1 + 125 {e}^{-\left( 0.8 \cdot 6.413 \right)}}&=20 \cdot \frac{1}{1 + 125 \cdot e^{- \frac{8}{10} \cdot \left(6 + \frac{413}{1000}\right)}}\\&=20 \cdot \frac{1}{1 + 125 \cdot e^{- \frac{8}{10} \cdot \frac{6413}{1000}}}\\&=20 \cdot \frac{1}{1 + 125 \cdot e^{- \frac{4}{5} \cdot \frac{6413}{1000}}}\\&=20 \cdot \frac{1}{1 + 125 \cdot e^{- \frac{6413}{1250}}}\\&=20 \cdot \frac{1}{1 + 125 \cdot \frac{1}{e^{\frac{6413}{1250}}}}\\&=20 \cdot \frac{1}{1 + 125 \cdot e^{- \frac{6413}{1250}}}\end{aligned}$$

$e$ is Euler's number, a mathematical constant that is approximately $2.71828$.