Let a, b, c be positive real numbers. Then find two real numbers x, y such that
1
2
loga
(4a
6
b
2
c
2
) − loga
(2b) = loga
(x) + y.
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
Let a, b, c be positive real numbers. Then find two real numbers x, y such that
1
2
loga
(4a
6
b
2
c
2
) − loga
(2b) = loga
(x) + y.
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.