5x5^{x}5x - 5x−15^{x-1}5x−1 / (4* 5x−15^{x-1}5x−1 )
asked by guest on Mar 22, 2025 at 7:35 pm
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MathBot Answer:
5x−5x−14⋅5x−1=5x−51−x5x−14\displaystyle {5}^{x} - \frac{{5}^{x - 1}}{4 \cdot {5}^{x - 1}} = 5^{x} - \frac{5^{1 - x} 5^{x - 1}}{4} 5x−4⋅5x−15x−1=5x−451−x5x−1
5x−5x−14⋅5x−1=5x−14{5}^{x} - \frac{{5}^{x - 1}}{4 \cdot {5}^{x - 1}} = 5^{x} - \frac{1}{4}5x−4⋅5x−15x−1=5x−41
5x−5x−14⋅5x−1=4⋅5x−14{5}^{x} - \frac{{5}^{x - 1}}{4 \cdot {5}^{x - 1}} = \frac{4 \cdot 5^{x} - 1}{4}5x−4⋅5x−15x−1=44⋅5x−1