x^2y"+xy'-16y=8x^3

asked by guest
on Jan 14, 2025 at 4:27 am



You asked:

Investigate the equation: \({x}^{2} \cdot y^{\prime \prime} + x \cdot y^{\prime} - 16 y = 8 {x}^{3}\).

MathBot Answer:

\[y{\left(x \right)} = \frac{\frac{x^{7} \left(-8 + C_{2} x\right)}{7} + C_{1}}{x^{4}}\]

\(C_{1}\), \(C_{2}\) are arbitrary constants.

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