fully factorize

9k^2 + 12k -20 = 0

asked by guest
on Sep 21, 2024 at 2:39 pm



You asked:

Factor the expression: \(\displaystyle 9 \cdot {k}^{2} + 12 k - 20 = 0\)

MathBot Answer:

Factorization over the real numbers:

\[20 \cdot \left(0.45 k^{2} + 0.6 k - 1\right)= 0\]

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