1/2(3-2x)(x+2)^2

asked by guest
on Apr 04, 2025 at 6:05 am



You asked:

Evaluate the expression: 12(3−2x)(x+2)2\frac{1}{2 \left(3 - 2 x\right) {\left( x + 2 \right)}^{2}}

MathBot Answer:

Evaluated



12(3−2x)(x+2)2=12⋅(3−2x)(x+2)2\displaystyle \frac{1}{2 \left(3 - 2 x\right) {\left( x + 2 \right)}^{2}} = \frac{1}{2 \cdot \left(3 - 2 x\right) \left(x + 2\right)^{2}}

Expanded

12(3−2x)(x+2)2=1−4x3−10x2+8x+24\frac{1}{2 \left(3 - 2 x\right) {\left( x + 2 \right)}^{2}} = \frac{1}{- 4 x^{3} - 10 x^{2} + 8 x + 24}

Factored

12(3−2x)(x+2)2=−12⋅(2x−3)(x+2)2\frac{1}{2 \left(3 - 2 x\right) {\left( x + 2 \right)}^{2}} = - \frac{1}{2 \cdot \left(2 x - 3\right) \left(x + 2\right)^{2}}

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