a=-2 b=3 find a^2 b^3
asked by guest on Nov 16, 2024 at 11:27 pm
MathBot Answer:
The system of linear equations has exactly one solution.
The substitutions are a=−2 a = -2 a=−2, b=3 b = 3 b=3.
a2=4{a}^{2} = 4a2=4
b3=27{b}^{3} = 27b3=27
