3^2x+4 +1=2*3^x+2

asked by guest
on Mar 25, 2025 at 10:22 pm



You asked:

Solve the equation 32x+4+1=2⋅3x+2{3}^{2} x + 4 + 1 = 2 \cdot {3}^{x} + 2 for the variable xx.

MathBot Answer:

The 2 solutions to the equation are: x=0.20852175296518245345031752883881297128219919039−log⁡(3)3log⁡(3)≈−0.14352865x=2.80909660368862210678515349359938806494242605398−log⁡(3)3log⁡(3)≈2.2236166\begin{aligned}x &= \frac{0.20852175296518245345031752883881297128219919039 - \frac{\log{\left(3 \right)}}{3}}{\log{\left(3 \right)}} \approx -0.14352865\\x &= \frac{2.80909660368862210678515349359938806494242605398 - \frac{\log{\left(3 \right)}}{3}}{\log{\left(3 \right)}} \approx 2.2236166\end{aligned}

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