5+2y-11=3-4+7y
asked by guest on Apr 02, 2025 at 11:57 pm
You asked:
MathBot Answer:
The solution is: y=−1y = -1y=−1
5+2y−11=3−4+7y2y−6=7y−1−5y=5y=−1\begin{aligned}5 + 2 y - 11 &= 3 - 4 + 7 y\\2 y - 6 &= 7 y - 1\\- 5 y &= 5\\y &= -1\end{aligned}5+2y−112y−6−5yy=3−4+7y=7y−1=5=−1
