((5χ/3)! * (χ/3)!)/((4χ/3)! * (2χ/3)!)
asked by guest on Jan 29, 2025 at 12:10 pm
You asked:
MathBot Answer:
(5χ3)!⋅(χ3)!(4χ3)!⋅(2χ3)!=(χ3)!(5χ3)!(2χ3)!(4χ3)!\frac{\left( \frac{5 χ}{3} \right)! \cdot \left( \frac{χ}{3} \right)!}{\left( \frac{4 χ}{3} \right)! \cdot \left( \frac{2 χ}{3} \right)!} = \frac{\left(\frac{χ}{3}\right)! \left(\frac{5 χ}{3}\right)!}{\left(\frac{2 χ}{3}\right)! \left(\frac{4 χ}{3}\right)!}(34χ)!⋅(32χ)!(35χ)!⋅(3χ)!=(32χ)!(34χ)!(3χ)!(35χ)!