antiderivative 1/x²

asked by guest
on Mar 30, 2025 at 9:42 am



You asked:

Evaluate the integral: ∫1x2dx\int{\frac{1}{{x}^{2}}}dx

MathBot Answer:

Antiderivative

∫1x2dx=−1x+C\int{\frac{1}{{x}^{2}}}dx = - \frac{1}{x} + C

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