Math Problem Solver

\[ \frac{15}{16} - \frac{1}{3} = \frac{29}{48} = 0.6041\overline{6} \]

The sum can be computed by rewriting each term over a common denominator, where the least common denominator of \(\frac{15}{16}\) and \(\frac{-1}{3}\) is \(48\). \[ \begin{aligned} \frac{15}{16} - \frac{1}{3} &= \frac{15 \cdot 3}{16 \cdot 3} + \frac{-1 \cdot 16}{3 \cdot 16} \\ &= \frac{45 + -16}{48} \\ &= \frac{29}{48} \end{aligned} \]