20i = ((1+i)^2)-1
You asked:
Solve the equation \(20 i = {\left( 1 + i \right)}^{2} - 1\) for the variable \(i\).
MathBot Answer:
This equation has no unknown quantities, so it is either true or false.
This equation is false because the left-hand side is not equal to the right-hand side.
The left-hand side of the equation is:
\[20 i\]The right-hand side of the equation is:
\[{\left( 1 + i \right)}^{2} - 1 = -1 + \left(1 + i\right)^{2}\]\(i\) is the imaginary unit, defined as \(i^2 = -1\).