(x+20) + (y-16)² = 144

C(-20,16) , r = 12

asked by guest
on Sep 22, 2024 at 9:22 am



You asked:

Solve the system of equations:\[\begin{aligned}x + 20 + {\left( y - 16 \right)}^{2} &= 144 \cdot C\left( -20, 16 \right)\\r &= 12\end{aligned}\]

MathBot Answer:

The system of equations has infinitely many solutions.

$$\begin{aligned}r &= 12\\x &= - y^{2} + 32 y + 584629768524\end{aligned}$$

\(y\) is a free variable.

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