cos2 theta - sin2 theta = 1/2 find tan2 theta
asked by guest
on Jan 24, 2025 at 7:08 pm
MathBot Answer:
θtan(2)=4cos(4π+2)2tan(2)
θ(−sin(2)+cos(2))θ=21=2(−sin(2)+cos(2))1
By substituting this value into the expression, we find that: θtan(2)=4cos(4π+2)2tan(2)=4cos(4π+2)2tan(2)