(t^2−5t+25 / 25t^2-1 ⋅ 5t^2+t / t^3+125 − t+5 / 5t^2−t) : 4 / t^2+5t − 25t+22 / 4−20t

asked by guest
on Nov 24, 2024 at 2:55 am



Mathbot Says...

I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.