Math Problem Solver

False, $\left( 2, \ 7\right)$ is not a solution of $y = 3 x + 1 \text{ and } y = 2 x + 5$.

$$\begin{gathered}y = 3 x + 1\\7 \stackrel{?}{=} 3 \left(2\right) + 1\\7 = 7\end{gathered}$$$$\begin{gathered}y = 2 x + 5\\7 \stackrel{?}{=} 2 \left(2\right) + 5\\7 \neq 9\end{gathered}$$