y = X^2/3 + 0.9sin (kx) √3-x^2 K= 100

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on Nov 23, 2024 at 12:54 pm



You asked:

Solve the system of equations:y=X23+0.9sin⁡(kx)⋅3−x2K=100\begin{aligned}y &= \frac{{X}^{2}}{3} + 0.9 \sin\left( k x \right) \cdot \sqrt{3} - {x}^{2}\\K &= 100\end{aligned}

MathBot Answer:

The system of equations has infinitely many solutions.

K=X23−x2+93sin⁡(kx)10X=100\begin{aligned}K &= \frac{X^{2}}{3} - x^{2} + \frac{9 \sqrt{3} \sin{\left(k x \right)}}{10}\\X &= 100\end{aligned}

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