The circle below has radius . Eight segment lengths are labeled with lowercase letters. Six of these equal trigonometric functions of . Your answer to this problem should be a six letter sequence whose letters represent the segment lengths that equal the following functions (in the correct order):
[asy]
size(200);
pair O,A,B,C,D;
O = (0,0);
A = rotate(55)*(1,0);
D = intersectionpoint(O--(3,0), A -- (A + scale(2)*rotate(-90)*A));
C = foot(A,O,D);
B = intersectionpoint(D -- (A + A - D), O -- (0,5));
draw(Circle(O,1));
draw(O--A--D--O--B--A--C);
//label("",A,SE);
label("",O,SW);
//label("",B,NW);
//label("",C,NW);
//label("",D,SE);
draw(rightanglemark(D,O,B,2));
draw(rightanglemark(B,A,O,2));
draw(rightanglemark(D,C,A,2));
draw("",(O-(0,0.12))--(C-(0,0.12)),blue,Bars(2mm));
draw("",(D-(0,0.12))--(C-(0,0.12)),S,red,Bars(2mm));
draw("",(O-(0,0.31))--(D-(0,0.31)),brown,Bars(2mm));
label("",(A+C)/2,E);
label("",(B/2),W);
pair T = A/10;
draw("",(B+T)--(A+T),NE,blue,Bars(2mm));
draw("",(A+T)--(D+T),NE,red,Bars(2mm));
draw("",(B+3*T)--(D+3*T),NE,brown,Bars(2mm));
label("",O+(0.1,0),NE);
label("",A/2,NW);
[/asy]
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