4^x + 2^2x-3 = 3^2/2^3

asked by guest
on Jan 25, 2025 at 11:39 pm



You asked:

Solve the equation 4x+22x−3=3223{4}^{x} + {2}^{2} x - 3 = \frac{{3}^{2}}{{2}^{3}} for the variable xx.

MathBot Answer:

The solution is: x=−0.71101612661003584836674340553803287869422967873+33log⁡(4)32log⁡(4)≈0.51836028x = \frac{-0.71101612661003584836674340553803287869422967873 + \frac{33 \log{\left(4 \right)}}{32}}{\log{\left(4 \right)}} \approx 0.51836028

+ Submit Question