( $\sqrt{\}$ $\sqrt{\ x }$ + $x^{2}$ )= f(x)
f'(x)=
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
( $\sqrt{\}$ $\sqrt{\ x }$ + $x^{2}$ )= f(x)
f'(x)=
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.