g(x)=x/(x-1) inverse
You asked:
Find the inverse of \(g\left( x \right) = \frac{x}{x - 1}\)
MathBot Answer:
The inverse of \(g\left( x \right) = \frac{x}{x - 1}\) is \(g^{-1}\left( x \right) =\frac{x}{x - 1}\).
g(x)=x/(x-1) inverse
You asked:
MathBot Answer:
The inverse of \(g\left( x \right) = \frac{x}{x - 1}\) is \(g^{-1}\left( x \right) =\frac{x}{x - 1}\).