\(\ln \left(9^{x}\right)=\ln \left(3^{x}+12\right)\)
You asked:
Solve the equation \(\ln\left( {9}^{x} \right) = \ln\left( {3}^{x} + 12 \right)\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{\log{\left(4 \right)}}{\log{\left(3 \right)}} \approx 1.2618595\]