ln⁡(9x)=ln⁡(3x+12)\ln \left(9^{x}\right)=\ln \left(3^{x}+12\right)

asked by guest
on Nov 27, 2024 at 3:45 am



You asked:

Solve the equation ln⁡(9x)=ln⁡(3x+12)\ln\left( {9}^{x} \right) = \ln\left( {3}^{x} + 12 \right) for the variable xx.

MathBot Answer:

The solution is: x=log⁡(4)log⁡(3)≈1.2618595x = \frac{\log{\left(4 \right)}}{\log{\left(3 \right)}} \approx 1.2618595

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