If 𝑥𝑥𝑦𝑦𝑧𝑧=𝑐, show that at 𝑥=𝑦=𝑧, 𝜕2𝑧
𝜕𝑥𝜕𝑦
=−((𝑥𝑙𝑜𝑔𝑒𝑥))−1
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
If 𝑥𝑥𝑦𝑦𝑧𝑧=𝑐, show that at 𝑥=𝑦=𝑧, 𝜕2𝑧
𝜕𝑥𝜕𝑦
=−((𝑥𝑙𝑜𝑔𝑒𝑥))−1
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.