y^4+16y=0
You asked:
Solve the equation \({y}^{4} + 16 y = 0\) for the variable \(y\).
MathBot Answer:
The 4 solutions to the equation are: \[\begin{aligned}y &= 0\\y &= - 2 \cdot \sqrt[3]{2} \approx -2.5198421\\y &= \sqrt[3]{2} + \sqrt[3]{2} \sqrt{3} i \approx 1.259921 + 2.1822473 i\\y &= \sqrt[3]{2} - \sqrt[3]{2} \sqrt{3} i \approx 1.259921 -2.1822473 i\end{aligned}\]
\(i\) is the imaginary unit, defined as \(i^2 = -1\).