Is (2,10) a solution to this system of equations?

y=x+8

y=10x+3

asked by guest
on Jan 16, 2025 at 8:28 am



MathBot Answer:

False, $\left( 2, \ 10\right)$ is not a solution of $y = x + 8 \text{ and } y = 10 x + 3$.


$$\begin{gathered}y = x + 8\\10 \stackrel{?}{=} 2 + 8\\10 = 10\end{gathered}$$$$\begin{gathered}y = 10 x + 3\\10 \stackrel{?}{=} 10 \left(2\right) + 3\\10 \neq 23\end{gathered}$$