a^3+9b^3+(a+b)^3
asked by guest on Feb 01, 2025 at 4:38 am
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MathBot Answer:
a3+9b3+(a+b)3=a3+9b3+(a+b)3\displaystyle {a}^{3} + 9 {b}^{3} + {\left( a + b \right)}^{3} = a^{3} + 9 b^{3} + \left(a + b\right)^{3} a3+9b3+(a+b)3=a3+9b3+(a+b)3
a3+9b3+(a+b)3=2a3+3a2b+3b2a+10b3{a}^{3} + 9 {b}^{3} + {\left( a + b \right)}^{3} = 2 a^{3} + 3 a^{2} b + 3 b^{2} a + 10 b^{3}a3+9b3+(a+b)3=2a3+3a2b+3b2a+10b3
a3+9b3+(a+b)3=(a+2b)(2a2−ab+5b2){a}^{3} + 9 {b}^{3} + {\left( a + b \right)}^{3} = \left(a + 2 b\right) \left(2 a^{2} - a b + 5 b^{2}\right)a3+9b3+(a+b)3=(a+2b)(2a2−ab+5b2)