(3x-1)^2
asked by guest on Apr 13, 2025 at 3:36 pm
You asked:
MathBot Answer:
(3x−1)2=(3x−1)2\displaystyle {\left( 3 x - 1 \right)}^{2} = \left(3 x - 1\right)^{2} (3x−1)2=(3x−1)2
(3x−1)2=9x2−6x+1{\left( 3 x - 1 \right)}^{2} = 9 x^{2} - 6 x + 1(3x−1)2=9x2−6x+1