9^(2pq+1) + 3^(4pq-3) = 732 express p in terms of q
You asked:
Given \({9}^{2 p q + 1} + {3}^{4 p q - 3} = 732\), express \(p\) in terms of the variable \(q\).
MathBot Answer:
$$\begin{aligned}p &= \frac{1}{q}\\p &= \frac{\log{\left(3 \right)} + i \pi}{q \log{\left(3 \right)}}\\p &= \frac{\log{\left(9 \right)} - i \pi}{2 q \log{\left(3 \right)}}\\p &= \frac{\log{\left(9 \right)} + i \pi}{2 q \log{\left(3 \right)}}\end{aligned}$$