7 × √7 × 7^3 ÷ 7^ -3/2 = 7^ x+2
You asked:
Solve the equation \(\frac{\frac{7 \cdot \sqrt{7} \cdot {7}^{3}}{{7}^{-3}}}{2} = {7}^{x} + 2\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = \frac{\log{\left(-2 + \frac{823543 \sqrt{7}}{2} \right)}}{\log{\left(7 \right)}} \approx 7.1437919\]